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Old 11-16-2004, 01:50   #1 (permalink)
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try to solve this

There were three guys at a bar, and they had to pay $30, so they paid $10 each.. so $10+$10+$10 = $30 But hey... there was a mistake, they had to pay $25 instead of $30 actually, so they got five $1 coins back and they leave a $2 tip. So here's the thing: Everyone payed $10, minus they $1 they got back, it's $9 each, so $9x3 = $27 + the $2 tip it's = $29, but in fact they payed $30... so where's the missing $1? Solve it and you might get the $1 :)
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Old 11-16-2004, 02:02   #2 (permalink)
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Re: try to solve this

simple, they didnt pay $30, they paid $25 plus a tip of $2.

either that or the dodgey bastard behind the bar gave himself a little bigger tip ...hehe
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Old 11-16-2004, 02:15   #3 (permalink)
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Re: try to solve this

Quote:
Originally Posted by LuKeY
There were three guys at a bar, and they had to pay $30, so they paid $10 each.. so $10+$10+$10 = $30 But hey... there was a mistake, they had to pay $25 instead of $30 actually, so they got five $1 coins back and they leave a $2 tip. So here's the thing: Everyone payed $10, minus they $1 they got back, it's $9 each, so $9x3 = $27 + the $2 tip it's = $29, but in fact they payed $30... so where's the missing $1? Solve it and you might get the $1 :)
They did not pay $29 overall, thay paid $27 ($30 - $5 + $2 tip = $27). There was no mention of them leaving $2 each (as that would have equalled $31), so they each received $1 in the end.
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Old 11-16-2004, 02:41   #4 (permalink)
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Re: try to solve this

Seen this one quite a few times. The first time you read it it is a little confusing, however that is because it is worded that way.

$30 (10+10+10) - $5 (1+1+1+2) = $25
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Old 11-16-2004, 02:48   #5 (permalink)
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Re: try to solve this

oops
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Old 11-16-2004, 03:42   #6 (permalink)
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Re: try to solve this

its worded wrong
they got $5 back and then tiped the guy $2 so therefor they got $1 each back :)
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Old 11-16-2004, 16:09   #7 (permalink)
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Re: try to solve this

Yeah...wot they sed.
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